WC130 寻找第K大 思路:快速排序后 # -*- coding:utf-8 -*- class Solution: def findKth(self, a, n, K): # write code here a_sort = self.quick_sort(a, 0, n-1) return a_sort[n-K] def quick_sort(self,l,left,right): if left >= right: return low = left ...