//本题为序列和问题,输出为等差数列 //Sn=n*(a1+an)/2=n*a1+n*(n-1)*d/2 //a1=(2*Sn-n*(n-1))/(2*n) #include<bits/stdc++.h> using namespace std; int main(){ int n=0; int l=0; scanf("%d",&n); scanf("%d",&l); for(int i=l;i<=100;i++){ if((2*n+i-i*i)%(2*i)==0){ int temp = (2*n+i-i*i)/(2*i); ...