用小于等于n元去买100只鸡,大鸡5元/只,小鸡3元/只,还有1/3元每只的一种小鸡,分别记为x只,y只,z只。编程求解x,y,z所有可能解。
(本题没有测试数据,
int main(){}就能通过
真·本地过了就是过了)
int main(){}就能通过
测试数据有多组,输入n。
对于每组输入,请输出x,y,z所有可行解,按照x,y,z依次增大的顺序输出。
40
x=0,y=0,z=100 x=0,y=1,z=99 x=0,y=2,z=98 x=1,y=0,z=99
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int n = scanner.nextInt(); for (int x = 0; x < 101; x++) { for (int y = 0; y < 101; y++) { for (int z = 0; z < 101; z++) { if (x+y+z==100&&x*5+y*3+z/3<=n) System.out.println("x="+x+",y="+y+",z="+z); } } } } }
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int n = scanner.nextInt(); for (int x = 0; x <= 100; x++) { for (int y = 0; y <= 100-x; y++) { int z=100 -y-x; if (x*5+y*3+z/3<=n) System.out.println("x="+x+",y="+y+",z="+z); } } } }
import java.util.Scanner; public class Main{ public static void main(String[] args){ Scanner sc = new Scanner(System.in); int n = sc.nextInt(); double x=5,y=3,z=1/3; int i,j,k; for(i=0; i<n/5;i++){ for(j=100-i;j<(n-5*i)/3;j++){ for(k=100-i-j;k<(n-5*i-3*j)*3;k++){ if((i+j+k)==100){ System.out.println("x="+i+",y="+j+",z="+k); } } } } } }
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
int x,y,z;
for(x=0; x<=100; x++) {
for(y=0; y<=100; y++) {
for(z=0; z<=100; z++) {
if(x+y+z==100 && 5*x+3*y+z/3<=n) {
System.out.println("x="+x+",y="+y+",z="+z);
}
}
}
}
}
}