TEG 一面面经（秒挂，个人水平太捞了）

import java.util.concurrent.atomic.AtomicInteger; public class AlternatePrintingNumbersAtomic { private static AtomicInteger count = new AtomicInteger(1); private static final int MAX_COUNT = 10; public static void main(String[] args) { Thread thread1 = new Thread(() -> { while (count.get() <= MAX_COUNT) { if (count.get() % 2 == 1) { System.out.println(Thread.currentThread().getName() + ": " + count.getAndIncrement()); } } }, "Thread1"); Thread thread2 = new Thread(() -> { while (count.get() <= MAX_COUNT) { if (count.get() % 2 == 0) { System.out.println(Thread.currentThread().getName() + ": " + count.getAndIncrement()); } } }, "Thread2"); thread1.start(); thread2.start(); } }

哪个部门呀

无锁应该是用内存模型那一套吧

atomic

正式批次吗

感谢分享

无锁可以用自旋

volatile加自旋

哪个部门啊

countdownlatch

是正式秋招吗

拼多多考虑吗，跨境电商机会多多，空间很大

teg云架构存储吗，这个很多人都一面秒挂了

确实看着很像架平的面试题

一样一面挂

自旋本质上不也是锁吗，这种解法能符合题意吗？

原子变量+自旋

佬，"不用加减乘除取模计算除法"怎么做呀，减法也不能用吗？