2020-09-08 21:24 Columbia University 产品经理
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#携程笔试# 请问各位大佬数据方向最后一道SQL
SELECT userid, cnt_1d, amt_1d, cnt_7d, amt_7d, cnt_15d, amt_15d
FROM
(SELECT userid, COUNT(*) as cnt_1d,SUM(amount) as amt_1d FROM edw_htl_order where orderdate between '2020-07-15' and '2020-07-16' group by userid)a
JOIN
(SELECT userid, COUNT(*) as cnt_7d,SUM(amount) as amt_7d FROM edw_htl_order where orderdate between '2020-07-09' and '2020-07-16' group by userid)b
on a.userid = b.userid
JOIN
(SELECT userid, COUNT(*) as cnt_15d,SUM(amount) as amt_15d FROM edw_htl_order where orderdate between '2020-07-01' and '2020-07-16' group by userid)c
on a.userid = c.userid
这个为啥过不了呀？每次合并SELECT查询都出问题
SELECT userid, cnt_1d, amt_1d, cnt_7d, amt_7d, cnt_15d, amt_15d
FROM
(SELECT userid, COUNT(*) as cnt_1d,SUM(amount) as amt_1d FROM edw_htl_order where orderdate between '2020-07-15' and '2020-07-16' group by userid)a
JOIN
(SELECT userid, COUNT(*) as cnt_7d,SUM(amount) as amt_7d FROM edw_htl_order where orderdate between '2020-07-09' and '2020-07-16' group by userid)b
on a.userid = b.userid
JOIN
(SELECT userid, COUNT(*) as cnt_15d,SUM(amount) as amt_15d FROM edw_htl_order where orderdate between '2020-07-01' and '2020-07-16' group by userid)c
on a.userid = c.userid
这个为啥过不了呀？每次合并SELECT查询都出问题
全部评论
不想泡池子的中国人allin春招
微软_数据科学家
第二个单词应该是a.userid, 否则他不知道是那个表里面的userid。改了后我可以运行成功了
foreverwinner
山东大学 数据分析师
为啥写的这么复杂呀，可以写6个case when只查询一次滴
白日梦Xxxxxn
门头沟学院 数据分析师
select userid
,count(case when orderdate >= '2020-07-15' and orderdate <= '2020-07-16' then orderid else null end) cnt_1d
,sum(case when orderdate >= '2020-07-15' and orderdate <= '2020-07-16' then amount else 0 end) amt_1d
,count(case when orderdate >= '2020-07-09' and orderdate <= '2020-07-16' then orderid else null end) cnt_7d
,sum(case when orderdate >= '2020-07-09' and orderdate <= '2020-07-16' then amount else 0 end) amt_7d
,count(case when orderdate >= '2020-07-01' and orderdate <= '2020-07-16' then orderid else null end) cnt_15d
,sum(case when orderdate >= '2020-07-01' and orderdate <= '2020-07-16' then amount else 0 end) amt_15d
from edw_htl_order
group by userid
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