小米笔试

小米测开的笔试算法题很简单1.第一题题目很简单，给一串小字符串和一个大字符串判断小字符串能不能拼接成大字符串 def read_every_t(): n, L = input().split(" ") n, L = int(n), int(L) s = [] s.extend(input().split(" ")) print(s) assert len(s) == n un_use = [True] * n mubiao = input() index = 0 h...

第一题import java.util.*;public class test {    public static void main(String[] args) {        Scanner in=new Scanner(System.in);        int n=in.nextInt();        int k=in.nextInt();        int[] a=new int[100005];        int ai;        int st=100005,ed=0;        for(int i=0;i<n;i++){             ai=in.nextInt();             a[ai]=1;             if(i==0) st=ai;             if(i==n-1) ed=ai;        }        int moreDay=k-n,ans=0,kDay=0;        TreeMap<Integer,Integer> kDayMap=new TreeMap<>();        for(int i=st-1;i<=ed+1;i++){            if(a[i]==0&&a[i+1]==1) {                ans++;                if(i<=st) continue;                kDay++;                if(kDayMap.containsKey(kDay)){                    kDayMap.put(kDay,kDayMap.get(kDay)+1);                }else kDayMap.put(kDay,1);//                System.out.println("day:"+i+"kDay:"+kDay);                kDay=0;            }            else if(a[i]==1&&a[i+1]==0) {                ans++;            }            else if(a[i]==0) kDay++;        }        Set<Integer> kDaySet=kDayMap.keySet();//        System.out.println(kDaySet+"/"+ans+"/"+moreDay);        for(int key:kDaySet){//            System.out.println(key);//            System.out.println(kDayMap.get(key));            int value=kDayMap.get(key);            if(key*value<=moreDay){                moreDay-=key*value;                ans-=value*2;            }else {                ans-=(moreDay/key)*2;                moreDay=0;            }            if(moreDay==0) break;//            System.out.println("key:"+key+" value:"+value+" moreday:"+moreDay+" ans:"+ans);        }        System.out.println(ans);//        System.out.println(moreDay);//        System.out.println(kDayMap);        in.close();    }}第二题来不及做打表#牛客创作赏金赛#

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