''' 10 2 1 0 0 1 0 1 0 1 0 1 ''' # 思路：确定填充每相邻K个0得到的总长度 N, K = [int(i) for i in input().strip().split()] temp_list = [int(i) for i in input().strip().split()] dp = [0] for i in range(N): if temp_list[i] == 0: dp.append(i + 1) dp.append(N + 1) # 遍历得到最大长度 max_len = 0 for i in range(K + 1, len(dp)): max_len = max(max_len, dp[i] - dp[i - K - 1] - 1) print(max_len)