题解 | 判断链表中是否有环
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
#
# @param head ListNode类
# @return bool布尔型
#
class Solution:
def hasCycle(self , head: ListNode) -> bool:
if head is None:
return False
object_set = set()
cur_node = head
while (cur_node.next):
if cur_node in object_set:
return True
object_set.add(cur_node)
cur_node = cur_node.next
return False

