题解 | 日期类
#include<iostream>
#include<stdio.h>
using namespace std;
bool leapyear(int n){
return n%4==0&&n%100!=0||n%400==0;
}
int main(){
int m;
int Y,M,D;
cin>>m;
while(m){
cin>>Y>>M>>D;
int month[]={31,leapyear(Y)?29:28,31,30,31,30,31,31,30,31,30,31};
if(D==month[M-1]){
if(M==12){
Y++;
M=1;
D=1;
}
else{
M++;
D=1;
}
}
else{
D++;
}
printf("%04d-%02d-%02d\n",Y,M,D);
m--;
}
}
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