题解 | 日期类

#include <cstdio>
#include <iostream>
using namespace std;
int mon[130]={0,31,28,31,30,31,30,31,31,30,31,30,31};
bool run(int year){
    return year%4==0&&year%100!=0 || year%400 == 0;
}
int main() {
    int m,a,b,c;
    cin>>m;
    while(m--){
        mon[2] = 28;
        cin>>a>>b>>c;
        if(run(a)){
            mon[2] = 29;
        }
        c++;
        if(c>mon[b]){
            b++;
            if(b>12) a++;
            c= 1;
        }
        printf("%04d-%02d-%02d\n",a,b,c);
    }
}
// 64 位输出请用 printf("%lld")