题解 | 整数与IP地址间的转换

def two_to_ten(n):
    f_n = n.split('.')
    f2_n = []
    for k in f_n:
        i = int(k)
        f2_n.append((bin(i)[2:]).rjust(8, '0'))
    f3 = ''.join(f2_n)
    return int(f3,2)

def ten_to_two(m):
    m = int(m)
    # 确保二进制字符串长度为32位
    f1 = bin(m)[2:].zfill(32)
    # 将32位二进制字符串分割成每8位一组
    f2 = [f1[i:i+8] for i in range(0, 32, 8)]
    finall = []
    for i in f2:
        finall.append(str(int(i, 2)))  # 将每个8位二进制字符串转换为十进制
    return '.'.join(finall)  # 使用点号连接所有十进制数

# 示例
m = 10
print(ten_to_two(m))  # 输出应该是 "0.0.0.10"
n = input().strip()
m = input().strip()
print(two_to_ten(n))
print(ten_to_two(m))