题解 | #比较版本号#

/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 比较版本号
 * @param version1 string字符串 
 * @param version2 string字符串 
 * @return int整型
 */
int compare(char* version1, char* version2 ) {
    // write code here
    int l1 = strlen(version1), l2 = strlen(version2);
    int i = 0, j = 0;
    while(i < l1 || j < l2) {
        char tmp1[1002], tmp2[1002];
        int i1 = 0, j1 = 0;
        long long temp1 = 0, temp2 = 0;
        while(i < l1 && version1[i] != '.') {
            while(i < l1 && version1[i] == '0') {
                i++;
            }
            if(version1[i] == '.' || i == l1) {
                tmp1[i1++] = '0';
                break;
            }
            tmp1[i1++] = version1[i++];
            printf("i1 is %d tmp1[i1] is %c\n", i1 - 1, tmp1[i1 - 1]);
        }
        for(int k = i1 - 1; k >= 0; k--) {
            temp1 = temp1 * 10 + (tmp1[k] - '0');
        }
        printf("temp1 : %lld\n", temp1);
        while(j < l2 && version2[j] != '.') {
            while(j < l2 && version2[j] == '0') j++;
            if(version2[j] == '.' || j == l2) {
                tmp2[j1++] = '0';
                break;
            }
            tmp2[j1++] = version2[j++];
            printf("j1 is %d tmp2[j1] is %c\n", j1 - 1, tmp2[j1 - 1]);
        }
        for(int k = j1 - 1; k >= 0; k--) {
            temp2 = temp2 * 10 + (tmp2[k] - '0');
        }
        printf("temp2 : %lld\n", temp2);
        if(temp1 > temp2) return 1;
        else if(temp1 < temp2) return -1;
        else {
            i++;
            j++;
        }
    }


    return 0;

}