题解 | #单组_字符串#

#include <stdio.h>
#include <stdlib.h>

int main() {
    int n;
    scanf("%d\n", &n);
    char* s = (char*)malloc((n + 1) * sizeof(char));

    for (int i = 0; i < n; i++) {
        char tmp;
        scanf("%c", &tmp); 
        s[n-i-1] = tmp;
    }

    printf("%s\n", s);  

    free(s);
    return 0;
}