题解 | #最小面积子矩阵#前缀和模板题,记住就行。
最小面积子矩阵
https://www.nowcoder.com/practice/8ef506fbab2742809564e1a288358554
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int m = sc.nextInt(); int k = sc.nextInt(); int[][] matrix = new int[n][m]; for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { matrix[i][j] = sc.nextInt(); } } int[][] prefixSum = new int[n + 1][m + 1]; for (int i = 1; i <= n; i++) { for (int j = 1; j <= m; j++) { prefixSum[i][j] = matrix[i - 1][j - 1] + prefixSum[i - 1][j] + prefixSum[i][j - 1] - prefixSum[i - 1][j - 1]; } } int ans = Integer.MAX_VALUE; for (int x1 = 1; x1 <= n; x1++) { for (int y1 = 1; y1 <= m; y1++) { for (int x2 = x1; x2 <= n; x2++) { for (int y2 = y1; y2 <= m; y2++) { int sum = prefixSum[x2][y2] - prefixSum[x1 - 1][y2] - prefixSum[x2][y1 - 1] + prefixSum[x1 - 1][y1 - 1]; if (sum >= k) { int area = (x2 - x1 + 1) * (y2 - y1 + 1); if (area < ans) ans = area; } } } } } System.out.println(ans == Integer.MAX_VALUE ? -1 : ans); } }