题解 | #数字翻转#

#include <stdio.h>
int rev(int n)
{
    int res = 0;
    while(n!=0)
    {
        res= res*10 + n%10;
        n = n/10;
    }
    return res;
}
int main() {
    int x, y;
    while (scanf("%d %d", &x, &y) != EOF) 
    { 
        int a,b,c;
        a = rev(x);
        b = rev(y);
        c = rev(a+b);
        printf("%d\n", c);
    }
    return 0;
}