题解 | #牛牛的digit#
牛牛的digit
https://www.nowcoder.com/practice/21b49f1f495f4280b8a96c415deaa3c4
#include <stdio.h> void dight(int x,int i) { int n = 1; while (i) { i--; n = n*10; } printf("%d\n",x%n); } int main() { int x,i; scanf("%d %d",&x,&i); dight(x,i); return 0; }