题解 | #记负均正II#

#include <iostream>
using namespace std;

int main()
{
    int val,cnt=0;
    double sum=0,n=0;
    while (cin >> val){
        if (val < 0) {
            cnt++;
        }
        else{
            sum += val;
            n++;
        }
    }
    cout << cnt <<endl;

    double ans;
    if (n!=0){
        ans = sum / n;
    }
    else {
        ans = 0;
    }
    
    printf("%0.1lf\n", ans);
    return 0;
}