题解 | #计算一元二次方程#
计算一元二次方程
https://www.nowcoder.com/practice/7da524bb452441b2af7e64545c38dc26
#include <stdio.h>
#include<math.h>
int main()
{
float a = 0.0;
float b = 0.0;
float c = 0.0;
float derta = 0.0;
while(scanf("%f %f %f",&a,&b,&c)!=EOF)
if (a == 0.0)
{
printf("Not quadratic equation");
}
else
{
derta = b * b - 4*a * c;
if (derta == 0)
{
float r = -b / (2 * a);
printf("x1=x2=%.2f\n", r==0?0:r); //这里容易想不到，若不这样写，结果是-0.00，不符合题目 要求
}
else if (derta > 0)
{
float t1 = (-b - sqrt(derta)) / (2 * a);
float t2 = (-b + sqrt(derta)) / (2 * a);
printf("x1=%.2f;x2=%.2f\n", t1, t2);
}
else
{
float shibu = -b / (2 * a);
float xubu = sqrt(-derta) / (2 * a);
printf("x1=%.2f-%.2fi;x2=%.2f+%.2fi\n", shibu, xubu, shibu, xubu);
}
}
return 0;
}
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