题解 | #球的半径和体积#

#include <bits/stdc++.h>
#include <cmath>
using namespace std;

int main(){
    int x0,y0,z0,x1,y1,z1;
    while(cin >>x0 >>y0 >>z0 >>x1 >>y1 >> z1){
        double r = sqrt(abs(((x1-x0)*(x1-x0) + (y1-y0)*(y1-y0) + (z1-z0)*(z1-z0))));
        double v = (4 * acos(-1) * pow(r,3)) / 3;

        printf("%.3lf %.3lf",r,v);
    }
}

1.立体两点距离公式

2.acos(-1)等于pai