题解 | #尼科彻斯定理#

#include <stdio.h>

int main() {
    int num;
    scanf("%d", &num);
    int total = num * num * num;
    int average = total / num;
    if (1) {
        printf("%d", average - num + 1);
        for (int i = 1; i < num; i++) {
            int tem = average - num + 1 + i * 2;
            printf("+%d", tem);
        }
    }
    return 0;
}
//5^3=21+23+25+27+29
//6^3=31+33+35+37+39+41