题解 | #KiKi求质数个数#
KiKi求质数个数
https://www.nowcoder.com/practice/d3a404ee0f8d41f98bf4707035d91086
public class Main{ public static void main(String[] args){ int i = 0; for(int j=100;j<1000;j++){ for(int k = 2;k<j;k++ ){ if(j%k==0){ break; } else if(k==j-1){ i+=1; } } } System.out.print(i); } }