题解 | #获得积分最多的人(三)#
获得积分最多的人(三)
https://www.nowcoder.com/practice/d2b7e2a305a7499fb310dc82a43820e8
WITH total_grade AS (
SELECT user_id, SUM(IF(type='add', grade_num, -grade_num)) AS grade
FROM grade_info
GROUP BY user_id
),
max_grade AS (
SELECT MAX(grade)
FROM total_grade
)
SELECT u.id, u.name, t.grade AS grade_num
FROM user AS u
INNER JOIN total_grade AS t
ON u.id = t.user_id
WHERE t.grade
IN (SELECT * FROM max_grade);
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