题解 | #插入二叉搜索树#
插入二叉搜索树
https://www.nowcoder.com/practice/4900db9ddfbd43a7a9841c6a408bacf2
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param root TreeNode类
# @param val int整型
# @return TreeNode类
#
class Solution:
def insertToBST(self , root: TreeNode, val: int) -> TreeNode:
# write code here
if val >= root.val:
if root.right:
self.insertToBST(root.right,val)
else:
root.right = TreeNode(val)
else:
if root.left:
self.insertToBST(root.left,val)
else:
root.left = TreeNode(val)
return root
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