题解 | #字符串加解密#

字符串加解密

https://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a

#include <iostream>
#include<string>
using namespace std;

int main() {
    string s1,s2;
    while (cin >> s1 >> s2) { // 注意 while 处理多个 case
        for(int i=0;i<s1.size();i++)//encoder
        {
            char tmp=s1[i];
            if(s1[i]=='9')
            {
                s1[i]='0';
            }
            else if(s1[i]=='z')
            {
                s1[i]='A';
            }
            else if(s1[i]=='Z')
            {
                s1[i]='a';
            }
            else if((97<=s1[i])&&(122>s1[i]))
            {
                s1[i]=s1[i]-31;
            }
            else if((65<=s1[i])&&(90>s1[i]))
            {
                s1[i]=s1[i]+33;
            }
            else{
                s1[i]=s1[i]+1;
            }
        }
        cout<<s1<<endl;

        for(int i=0;i<s2.size();i++)//decoder
        {
            char tmp=s2[i];
            if(s2[i]=='0')
            {
                s2[i]='9';
            }
            else if(s2[i]=='A')
            {
                s2[i]='z';
            }
            else if(s2[i]=='a')
            {
                s2[i]='Z';
            }
            else if((97<s2[i])&&(122>=s2[i]))
            {
                s2[i]=s2[i]-33;
            }
            else if((65<s2[i])&&(90>=s2[i]))
            {
                s2[i]=s2[i]+31;
            }
            else{
                s2[i]=s2[i]-1;
            }
        }
        cout<<s2<<endl;

    }
}
// 64 位输出请用 printf("%lld")

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