题解 | #删除字符串中出现次数最少的字符#

s1=input()
se1=set(s1)
li2=list(se1)
#print(li2)
li=[]
for i in se1:
    n=0
    for j in s1 :        
        if i==j:
            n+=1
    li.append(n)
min1=min(li)
#print(min1)
li1=[]
dic1={k:v for k,v in zip(li2,li)}
#print(dic1)

for i in dic1.items():
    if i[1]==min1:
        li1.append(i[0])
for i in li1:
    s1=s1.replace(i,'')
print(s1)