题解 | #称砝码#
称砝码
https://www.nowcoder.com/practice/f9a4c19050fc477e9e27eb75f3bfd49c
#include <iostream> #include <vector> using namespace std; int main() { int n; while (cin >> n) { // 注意 while 处理多个 case vector<int> weight(n); int sum = 0; for (int i = 0; i < n; i++) cin >> weight[i]; for (int i = 0; i < n; i++) { int nums; cin >> nums; sum += nums * weight[i]; while (--nums) { weight.push_back(weight[i]); } } vector<int> dp(sum + 1, 0); dp[0] = 1; for (int i = 0; i < weight.size(); i++) { // 表示j重量是否可以称到 for (int j = sum; j >= weight[i]; j--) { if (dp[j]) continue; dp[j] = dp[j - weight[i]]; } } sum = 0; for (int i : dp) sum += i; cout << sum << endl; } return 0; } // 64 位输出请用 printf("%lld")