题解 | #数组中只出现一次的两个数字#

using System;
using System.Collections.Generic;


class Solution {
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     *
     * @param nums int整型一维数组
     * @return int整型一维数组
     */
    public List<int> FindNumsAppearOnce (List<int> nums) {
        // write code here
        for (int i = 0; i < nums.Count; i++) {
            int nF = nums.FindIndex(r => r == nums[i]);
            int nL = nums.FindLastIndex(r => r == nums[i]);
            if (nF != nL) {
                nums[nL] = nums[nF] = 0;
            }
        }
        List<int> ls = new List<int>();
        for (int i = 0; i < nums.Count; i++) {
            if (nums[i] == 0)
                continue;
            ls.Add(nums[i]);
        }
        return ls[0] > ls[1] ? new List<int>(2){ ls[1], ls[0] } : ls;
    }
}