题解 | #吃糖果#
吃糖果
https://www.nowcoder.com/practice/72015680c32b449899e81f1470836097
#include <bits/stdc++.h>
using namespace std;
int main() {
int N;//N块巧克力
int dp[21] = {0};
dp[1] = 1;
dp[2] = 2;
for (int i = 3; i <= 20; ++i) {
dp[i] = dp[i - 1] + dp[i - 2];
}
while (scanf("%d", &N) != EOF) {
printf("%d\n", dp[N]);
}
return 0;
}
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