题解 | #n的阶乘#
n的阶乘
https://www.nowcoder.com/practice/97be22ee50b14cccad2787998ca628c8
def cal_num(n):
if n == 1:
return 1
else: return n*cal_num(n-1)
while True:
try:
num = int(input())
print(cal_num(num))
except EOFError:
break
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