题解 | #求int型正整数在内存中存储时1的个数#

#include <stdio.h>
#include <string.h>

int main() {
    int n;
    int a[33];
    scanf("%d", &n);
    int l = 0;
    while (n / 2 > 0) {
        a[l] = n % 2;
        l++;
        n /= 2;
    }
    a[l] = n % 2;
    int count = 0;
    int i;
    for (i = 0; i <= l; i++) {
        if (a[i] == 1)
            count++;
    }
    printf("%d\n", count);
    return 0;
}