题解 | #删除字符串中出现次数最少的字符#

def remove_least_frequent_chars(s):
    # 统计每个字符的出现次数
    char_count = {}
    for char in s:
        if char in char_count:
            char_count[char] += 1
        else:
            char_count[char] = 1

    # 找出出现次数最少的字符的出现次数
    min_count = min(char_count.values())

    # 构建并返回一个新字符串，只包含出现次数不是最少的字符
    return "".join(char for char in s if char_count[char] != min_count)


# 输入
s = input()

# 输出
print(remove_least_frequent_chars(s))