题解 | #回文字符串#
回文字符串
https://www.nowcoder.com/practice/df00c27320b24278b9c25f6bb1e2f3b8
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
while (getline(cin,s)) { // 注意 while 处理多个 case
string s2 =s;
reverse(s.begin(),s.end());
if(s == s2)cout<<"Yes!"<<endl;
else cout<<"No!"<<endl;
}
}
// 64 位输出请用 printf("%lld")
qd
