题解 | #句子逆序#
句子逆序
https://www.nowcoder.com/practice/48b3cb4e3c694d9da5526e6255bb73c3
#include <stdio.h>
#include <string.h>
void printWord(char* w)
{
char ch = *w;
while(ch != ' ' && ch != 0)
{
if((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z'))
{
printf("%c",ch);
}
ch = *(++w);
}
}
int main() {
char str[1000] = {0};
char ch = 0;
int len = 0;
while('\n' != (ch = getchar()))
{
str[len++] = ch;
}
int wordEndp = len-1;
for(int i = len-1; i >= 0; i--)
{
if(' ' == str[i] )
{
printWord(&str[i+1]);
printf(" ");
}
else if( 0 == i)
printWord(&str[i]);
}
return 0;
}
#句子逆序#
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