题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
class ListNode: def __init__(self, x): self.val = x self.next = None # # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param head ListNode类 # @param m int整型 # @param n int整型 # @return ListNode类 # class Solution: def reverseBetween(self, head: ListNode, m: int, n: int) -> ListNode: if not head: return None # 创建一个虚拟节点 dummy,作为链表的起始点 dummy = ListNode(0) dummy.next = head # 初始化指针 pre = dummy for _ in range(m - 1): pre = pre.next # 反转链表 cur = pre.next for _ in range(n - m): temp = cur.next cur.next = temp.next temp.next = pre.next pre.next = temp return dummy.next