题解 | #牛客每个人最近的登录日期(四)#

牛客每个人最近的登录日期(四)

https://www.nowcoder.com/practice/e524dc7450234395aa21c75303a42b0a

with t2 as(
    select date from login group by date
)
select date,sum(if(first_date = date,1,0))
from t2 left join login using(date) left join(
    select min(date) first_date,user_id
    from login
    group by user_id
)t1 using(user_id)
group by date
order by date

全部评论

相关推荐

点赞 收藏 评论
分享
牛客网
牛客企业服务