题解 | #牛牛的替换#

#include <stdio.h>

int main() 
{
    int n = 0;
    char a1 = 0;
    char a2 = 0;
    char a3 = 0;
    char a4 = 0;
    scanf("%d %c %c %c %c", &n, &a1, &a2, &a3, &a4);
    getchar();//吸收换行符
    char str[100] =  { 0 };
    for (int i = 0; i < n; i++)
    {
        scanf("%c", &str[i]);
        if (str[i] == a1)
        {
            str[i] = a2;
        }
        if (str[i] == a3)
        {
            str[i] = a4;
        }
        
        //吸收换行符
    }
    //输出
    printf("%s\n", str);
    return 0;
}