题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
s = input().split()
N = int(s[0])
ls =[]
ls.append(s[1])
for i in range(1,N):
v = s[2*i]
pre = s[2*i + 1]
ls.insert(ls.index(pre) + 1,v)
ls.remove(s[-1])
for k in ls:
print(k,end=' ')
字节跳动公司氛围 570人发布
