题解 | #反转链表#
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ #include <bits/types/struct_tm.h> #include <cstddef> class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @return ListNode类 */ ListNode* ReverseList(ListNode* head) { // write code here if (head == nullptr) return nullptr; ListNode* cur = head; ListNode* pre = nullptr; while (cur != nullptr) { ListNode *tmp = cur->next; cur->next = pre; pre = cur; cur = tmp; } return pre;; } };