题解 | #记负均正#

#include <stdio.h>

int main() 
{
    int n = 0;
    scanf("%d",&n);
    int arr[n];
    int count1 = 0;
    float sum = 0.0;
    int count2 = 0;
    for(int i = 0;i < n;i++)
    {
        scanf("%d",&arr[i]);
        if(arr[i] < 0)
        {
            count1++;
        }
        else if(arr[i] > 0)
        {
            
            sum += arr[i];
        }
        else
        {
            count2++;
        }
    }
    if(count2 != n)
    {
        printf("%d %.1f\n",count1,sum / (n - count1 - count2));
    }
    else
    {
        printf("0 0.0");
    }
    return 0;
}