题解 | #牛牛的快递#
牛牛的快递
https://www.nowcoder.com/practice/41b42e7b3c3547e3acf8e90c41d98270
#include <stdio.h>
int main() {
float a;//快递重量
char b;//是否加急y/n
int fee = 0, A;
scanf("%f", &a);
getchar();
b = getchar();
int d = (int)a;
if (a == d)
A = a;
else
A = a + 1;
if (1 == A) {
if (b == 'y')
fee = 25;
else
fee = 20;
} else {
if (b == 'y')
fee = 25 + (A - 1);
else
fee = 20 + (A - 1);
}
printf("%d", fee);
return 0;
}
