题解 | #KiKi求质数个数#

#include <stdio.h>
#include<math.h>
int main() {
    int i = 0, j = 0, flag = 0, count = 0;
    for (i = 101; i < 1000; i += 2) {
        flag = 1;
        for (j = 2; j <= sqrt(i); j++) {
            if (i % j == 0) {
                flag = 0;
                break;
            }
        }
        if (1 == flag)
            count++;
    }
    printf("%d", count);

    return 0;
}