题解 | #简单计算器#
简单计算器
https://www.nowcoder.com/practice/b8f770674ba7468bb0a0efcc2aa3a239
#include <stdio.h>
int main() {
double a = 0.0, b = 0.0;
char c = 0;
scanf("%lf%c%lf", &a, &c, &b);
if (c != '+' && c != '-' && c != '*' && c != '/')
printf("Invalid operation!");
else
{
if (b == 0.0 && c == '/')
printf("Wrong!Division by zero!");
else
{
switch (c) {
case '+': printf("%.4f+%.4f=%.4f", a, b, a + b); break;
case '-': printf("%.4f-%.4f=%.4f", a, b, a - b); break;
case '*': printf("%.4f*%.4f=%.4f", a, b, a * b); break;
case '/': printf("%.4f/%.4f=%.4f", a, b, a / b); break;
}
}
}
return 0;
}
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