题解 | #牛牛的水杯#
牛牛的水杯
https://www.nowcoder.com/practice/c196c47c23394bf3bdd4f82a838df6bf
#include <stdio.h>
#include<math.h>
int main() {
int h,r;
scanf("%d %d",&h,&r);
int water = 0;
water = 3.14*h*pow(r,2);
int L = 10000;
if(L % water == 0)
{
printf("%d",L/water);
}
else {
printf("%d",(L / water)+1);
}
return 0;
}
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