题解 | #字符串反转#
字符串反转
https://www.nowcoder.com/practice/e45e078701ab4e4cb49393ae30f1bb04
line = input('', 's'); line_fliplr = []; for ii = 1 : length(line) line_fliplr(ii) = line(length(line) - ii +1); end printf("%s\n",line_fliplr);
字符串反转
https://www.nowcoder.com/practice/e45e078701ab4e4cb49393ae30f1bb04
line = input('', 's'); line_fliplr = []; for ii = 1 : length(line) line_fliplr(ii) = line(length(line) - ii +1); end printf("%s\n",line_fliplr);
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