题解 | #牛牛的线段#
牛牛的线段
https://www.nowcoder.com/practice/f72c56ed71664af082c921bf79861c85
#include <stdio.h>
#include <math.h>
int main() {
int x1, x2;
int y1,y2;
int s;
scanf("%d %d", &x1, &y1);
scanf("%d %d", &x2, &y2);
s=pow((x1-x2),2)+pow((y1-y2),2);
printf("%d",s);
return 0;
}
有点粗心，仔细看题目！！！
