题解 | #有效括号序列#
有效括号序列
https://www.nowcoder.com/practice/37548e94a270412c8b9fb85643c8ccc2
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param s string字符串 # @return bool布尔型 # class Solution: def isValid(self , s: str) -> bool: if len(s)%2 != 0: return False # 长度不是2的倍数肯定不行 stack = [] for char in s: try: if char == ')': if stack[-1] == '(': stack.pop() else: return False elif char == ']': if stack[-1] == '[': stack.pop() else: return False elif char == '}': if stack[-1] == '{': stack.pop() else: return False else: stack.append(char) except: return False return len(stack)==0