题解 | #计算日期到天数转换#

#include <stdio.h>

int is_years(int y)
{
    if (y % 4 == 0 && y % 100 != 0)
    {
        return 1;
    }
    if (y % 400 == 0)
    {
        return 1;
    }
    return 0;
}

int main() {
    int y = 0;
    int m = 0;
    int d = 0;
    int ret = 0;
    int days[13] = {0,31,0,31,30,31,30,31,31,30,31,30,31};
    while (scanf("%d %d %d", &y, &m, &d) != EOF) { // 注意 while 处理多个 case
        // 64 位输出请用 printf("%lld") to 
        if (is_years(y))
        {
            days[2] = 29;
        }
        else
        {
            days[2] = 28;
        }
        for (int i = 1; i < m; i++)
        {
            ret += days[i];
        }
        ret += d;
    }
    printf("%d\n", ret);
    return 0;
}