题解 | #从单向链表中删除指定值的节点#

import java.util.*;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        while (in.hasNext()) { // 注意 while 处理多个 case
            String str = in.nextLine();
            String[] strs = str.split(" ");
            int n = Integer.parseInt(strs[0]);
            int firstValue = Integer.parseInt(strs[1]);
            int aimValue = Integer.parseInt(strs[strs.length - 1]);
            LinkedList<Integer> list = new LinkedList<Integer>();
            list.add(firstValue);
            for (int i = 2; i < strs.length - 1; i += 2) {
                int position = list.indexOf(Integer.parseInt(strs[i + 1]));
                list.add(position, Integer.parseInt(strs[i]));
            }
            list.remove(list.indexOf(aimValue));
            Collections.reverse(list);
            for(Integer i : list) 
                System.out.print(i+" ");
        }
    }
}