题解 | #二叉树的后序遍历#

import java.util.*;

/*
 * public class TreeNode {
 *   int val = 0;
 *   TreeNode left = null;
 *   TreeNode right = null;
 *   public TreeNode(int val) {
 *     this.val = val;
 *   }
 * }
 */

public class Solution {
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     * 
     * @param root TreeNode类 
     * @return int整型一维数组
     */
    public int[] postorderTraversal (TreeNode root) {
        // write code here
        ArrayList<Integer> list = new ArrayList<Integer>();
        postorder(list, root);
	  //ArrayList传给int数组
        int[] ret = new int[list.size()];
        for(int i = 0; i < list.size(); i++){
            ret[i] = list.get(i);
        }
        return ret;
    }

    public void postorder (ArrayList<Integer> list, TreeNode root) {
        // 左右根
        if(root == null) return;
        postorder(list, root.left);
        postorder(list, root.right);
        list.add(root.val);
    }
}