题解 | #字符串变形#
字符串变形
https://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param s string字符串
# @param n int整型
# @return string字符串
#
class Solution:
def trans(self , s: str, n: int) -> str:
# write code here
new_words = []
words = s.split(' ')
for word in words:
new_word = ''
for i in range(len(word)):
ch = word[i]
if ch.lower() == ch:
new_word += ch.upper()
else:
new_word += ch.lower()
new_words.append(new_word)
return ' '.join(new_words[::-1])

