题解 | #字符串变形#
字符串变形
https://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param s string字符串 # @param n int整型 # @return string字符串 # class Solution: def trans(self , s: str, n: int) -> str: # write code here new_words = [] words = s.split(' ') for word in words: new_word = '' for i in range(len(word)): ch = word[i] if ch.lower() == ch: new_word += ch.upper() else: new_word += ch.lower() new_words.append(new_word) return ' '.join(new_words[::-1])